MHT CET · Chemistry · Electrochemistry
Pure dihydrogen (99.5\%) is obtained by the electrolysis of
- A \(\mathrm{NaOH}_{(\mathrm{aq})}\) using \(\mathrm{Zn}\) electrode
- B pure water
- C dil. \(\mathrm{H}_2 \mathrm{SO}_4\) using cadmium electrodes
- D warm barium hydroxide using \(\mathrm{Ni}\) electrodes
Answer & Solution
Correct Answer
(D) warm barium hydroxide using \(\mathrm{Ni}\) electrodes
Step-by-step Solution
Detailed explanation
- In the laboratory, high purity compounds can be obtained only with electrolysis.
- \(\quad\) Similarly, highly purified dihydrogen is also obtained by electrolyzing water using a small amount of acid or base.
- Here, \(\mathrm{Ba}(\mathrm{OH})_2\) is a base. Hence, electrolyzing water in the presence of a base \(\mathrm{Ba}(\mathrm{OH})_2\) gives us the highly purified (> \(99.95 \%\) ) Dihydrogen \(\left(\mathrm{H}_2\right)\) using Ni electrodes.
- \(\quad\) Similarly, highly purified dihydrogen is also obtained by electrolyzing water using a small amount of acid or base.
- Here, \(\mathrm{Ba}(\mathrm{OH})_2\) is a base. Hence, electrolyzing water in the presence of a base \(\mathrm{Ba}(\mathrm{OH})_2\) gives us the highly purified (> \(99.95 \%\) ) Dihydrogen \(\left(\mathrm{H}_2\right)\) using Ni electrodes.
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