MHT CET · Chemistry · Redox Reactions
Oxidation state of manganese in potassium permanganate is:
- A \(+3\)
- B \(+7\)
- C \(+5\)
- D \(+1\)
Answer & Solution
Correct Answer
(B) \(+7\)
Step-by-step Solution
Detailed explanation
Oxidation number of \(\mathrm{K}=+1\)
Oxidation number of \(\mathrm{O}=-2\)
\(\mathrm{KMnO}_4\) is a neutral molecule.
\(\therefore \quad\) Sum of the oxidation number of all atoms \(=0\)
Oxidation number of \(\mathrm{K}+\) Oxidation number of \(\mathrm{Mn}+4 \times(\) Oxidation number of \(\mathrm{O})=0\)
\((+1)+(\) Oxidation number of \(\mathrm{Mn})+4 \times(-2)=0\)
\(1+(\) Oxidation number of \(\mathrm{Mn})=+8\)
\(\therefore \quad\) Oxidation number of \(\mathrm{Mn}=+7\)
Oxidation number of \(\mathrm{O}=-2\)
\(\mathrm{KMnO}_4\) is a neutral molecule.
\(\therefore \quad\) Sum of the oxidation number of all atoms \(=0\)
Oxidation number of \(\mathrm{K}+\) Oxidation number of \(\mathrm{Mn}+4 \times(\) Oxidation number of \(\mathrm{O})=0\)
\((+1)+(\) Oxidation number of \(\mathrm{Mn})+4 \times(-2)=0\)
\(1+(\) Oxidation number of \(\mathrm{Mn})=+8\)
\(\therefore \quad\) Oxidation number of \(\mathrm{Mn}=+7\)
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