MHT CET · Chemistry · d and f Block Elements
Most basic hydroxide among the following is
- A \(\mathrm{Lu}(\mathrm{OH})_{3}\)
- B \(\mathrm{Eu}(\mathrm{OH})_{3}\)
- C \(\mathrm{Yb}(\mathrm{OH})_{3}\)
- D \(\mathrm{Ce}(\mathrm{OH})_{3}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{Ce}(\mathrm{OH})_{3}\)
Step-by-step Solution
Detailed explanation
Due to lanthanide contraction, the size of \(M^{3+}\) ions [ie, \(\mathrm{Lu}^{3+}, \mathrm{Eu}^{3+}, \mathrm{Yb}^{3+}\) and \(\mathrm{Ce}^{3+}\) ] decreases
and thus, the basic strength of their hydroxides decreases.
The order of size of given \(M^{3+}\) ions is \(\mathrm{Ce}^{3+}>\mathrm{Eu}^{3+}>\mathrm{Yb}^{3+}>\mathrm{Lu}^{3+}\)
\(\therefore\) The order of basic strength of hydroxides is \(\mathrm{Ce}(\mathrm{OH})_{3}>\mathrm{Eu}(\mathrm{OH})_{3}>\)\(\mathrm{Yb}(\mathrm{OH})_{3}>\mathrm{Lu}(\mathrm{OH})_{3}\)
(most basic)
and thus, the basic strength of their hydroxides decreases.
The order of size of given \(M^{3+}\) ions is \(\mathrm{Ce}^{3+}>\mathrm{Eu}^{3+}>\mathrm{Yb}^{3+}>\mathrm{Lu}^{3+}\)
\(\therefore\) The order of basic strength of hydroxides is \(\mathrm{Ce}(\mathrm{OH})_{3}>\mathrm{Eu}(\mathrm{OH})_{3}>\)\(\mathrm{Yb}(\mathrm{OH})_{3}>\mathrm{Lu}(\mathrm{OH})_{3}\)
(most basic)
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