MHT CET · Chemistry · Ionic Equilibrium
Molar conductivity of 0.02 M weak acid is \(7.92 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\) and its molar conductivity at infinite dilution is \(232.7 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\). Calculate degree of dissociation of weak acid.
- A 0.0112
- B 0.0341
- C 0.0694
- D 0.292
Answer & Solution
Correct Answer
(B) 0.0341
Step-by-step Solution
Detailed explanation
Degree of dissociation \((\alpha)=\frac{\wedge_c}{\wedge_0}\)
\(=\frac{7.92 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}}{232.7 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}}=0.0341\)
\(=\frac{7.92 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}}{232.7 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}}=0.0341\)
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