MHT CET · Chemistry · States of Matter
Keeping temperature constant the pressure of \(11.2 \mathrm{dm}^3\) of a gas was increased from \(105 \mathrm{kPa}\) to \(420 \mathrm{kPa}\). What is the new volume of gas?
- A \(1.4 \mathrm{dm}^3\)
- B \(7.0 \mathrm{dm}^3\)
- C \(5.6 \mathrm{dm}^3\)
- D \(2.8\mathrm{dm}^3\)
Answer & Solution
Correct Answer
(D) \(2.8\mathrm{dm}^3\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{P}_1 \mathrm{~V}_1=\mathrm{P}_2 \mathrm{~V}_2 \\ & 105 \times 11.2=420 \times \mathrm{V}_2 \\ & \mathrm{~V}_2=\frac{105 \times 11.2}{420} \\ & 2.8 \mathrm{dm}^3\end{aligned}\)
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