MHT CET · Chemistry · Amines
In the following reaction sequence, \(\mathrm{CH}_{3} \mathrm{CHO} \frac{\mathrm{Cl}_{2}}{\mathrm{Ca}(\mathrm{OH})_{2}} \times \frac{\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}}{\mathrm{Alc} . \mathrm{KOH}} Y\)
\(Y\) is
- A \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{NHC}_{6} \mathrm{H}_{5}\)
- B \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NHCH}_{3}\)
- C \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NC}\)
- D \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NCO}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NC}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{CH}_{3} \mathrm{CHO}+\mathrm{Cl}_{2} \longrightarrow \underset{\text { chloral }}{\mathrm{CCl}_{3} \mathrm{CHO}} \stackrel{\mathrm{Ca}(\mathrm{OH})_{2}}{\longrightarrow} \underset{\begin{array}{c}\text { Chloroform } \\ (X)\end{array}}{\mathrm{CHCl}_{3}}\)


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