MHT CET · Chemistry · Electrochemistry
In the cell represent as \(\mathrm{Ni}_{(\mathrm{s})}\left|\mathrm{Ni}_{(\mathrm{MM})}^{2^{\oplus}}\right|\left|\mathrm{Ag}_{(\mathrm{IM})}^{\oplus}\right| \mathrm{Ag}_{(\mathrm{s})}\), the reducing agent is
- A \(\mathrm{Ag}\)
- B \(\mathrm{Ag}^{\oplus}\)
- C \(\mathrm{Ni}\)
- D \(\mathrm{Ni}^{2 \oplus}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{Ni}\)
Step-by-step Solution
Detailed explanation
Anode Half cell: \(\mathrm{Ni}_{(\mathrm{s})} \stackrel{\text { Oxidation }}{\longrightarrow} \mathrm{Ni}^{2+}+2 \mathrm{e}^{-}\)
Cathode Half-cell, \(\mathrm{e}^{-}+\mathrm{Ag}^{+} \stackrel{\text { Reduction }}{\longrightarrow} \mathrm{Ag}_{(\mathrm{s})}\)
Reducing Agent is \(\mathrm{Ni}_{(\mathrm{s})}\)
Cathode Half-cell, \(\mathrm{e}^{-}+\mathrm{Ag}^{+} \stackrel{\text { Reduction }}{\longrightarrow} \mathrm{Ag}_{(\mathrm{s})}\)
Reducing Agent is \(\mathrm{Ni}_{(\mathrm{s})}\)
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