MHT CET · Chemistry · Chemical Kinetics
In the Arrhenius plot of logk versus \(1 / T\) find the value of intercept on \(y\) axis
- A \(\log _{10} \mathrm{~A}\)
- B \(\frac{-\mathrm{Ea}}{\mathrm{R}}\)
- C \(\ln k\)
- D \(R / E_a\)
Answer & Solution
Correct Answer
(A) \(\log _{10} \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
The Arrhenius equation is
\(\begin{aligned}
& k=A e^{-E_a / R T} \\
\therefore \quad & \ln k=-\frac{E_a}{R T}+\ln A
\end{aligned}\)
\(\therefore \quad \log _{10} \mathrm{k}=-\frac{\mathrm{E}_{\mathrm{a}}}{2.303 \mathrm{R}} \frac{1}{\mathrm{~T}}+\log _{10} \mathrm{~A}\)
Thus, the value of intercept on y axis is \(\log _{10} \mathrm{~A}\).
\(\begin{aligned}
& k=A e^{-E_a / R T} \\
\therefore \quad & \ln k=-\frac{E_a}{R T}+\ln A
\end{aligned}\)
\(\therefore \quad \log _{10} \mathrm{k}=-\frac{\mathrm{E}_{\mathrm{a}}}{2.303 \mathrm{R}} \frac{1}{\mathrm{~T}}+\log _{10} \mathrm{~A}\)
Thus, the value of intercept on y axis is \(\log _{10} \mathrm{~A}\).
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