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MHT CET · Chemistry · Solid State

In ionic solid, anions are arranged in ccp array and cations occupy \(1 / 3\) tetrahedral voids. What is the formula of ionic compound?
[Consider \(\mathrm{A}=\) cation \(; \mathrm{B}=\) anion]

  1. A \(\mathrm{AB}_3\)
  2. B \(\mathrm{A}_3 \mathrm{B}_2\)
  3. C \(\mathrm{A}_2 \mathrm{B}_3\)
  4. D \(\mathrm{AB}_4\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\mathrm{A}_2 \mathrm{B}_3\)

Step-by-step Solution

Detailed explanation

Number of B ions (ccp) \( = 4 \). Total tetrahedral voids \( = 2 \times 4 = 8 \).