MHT CET · Chemistry · Hydrocarbons
In Clemmensen's reduction, the catalyst used is
- A \(\mathrm{Zn}-\mathrm{Hg}+\) Conc \(\mathrm{HCl}\)
- B \(\mathrm{NH}_{2} \mathrm{NH}_{2}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{ONa}\)
- C \(\mathrm{PdCl}_{2} / \mathrm{H}_{2} \mathrm{O}\)
- D \(\left(\mathrm{C}_{6} \mathrm{H}_{5}\right)_{3} \mathrm{P}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{ONa}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{Zn}-\mathrm{Hg}+\) Conc \(\mathrm{HCl}\)
Step-by-step Solution
Detailed explanation
Zinc amalgam \((\mathrm{Zn}-\mathrm{Hg})\) and conc \(\mathrm{HCl}\) is used as a catalyst for Clemmensen's reduction. This reagent converts \(\sum \mathrm{C}=\mathrm{O}\) group to
\(>\mathrm{CH}_{2}\)
group.
\(>\mathrm{CH}_{2}\)
group.
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