MHT CET · Chemistry · Solid State
In an ionic solid anions are arranged in hcp array and cations occupy \(\frac{2}{3}\) of octahedral voids. What is the formula of ionic compound? [ consider \(\mathrm{A}=\) cation ; \(\mathrm{B}=\) anion]
- A AB
- B \(\mathrm{A}_2 \mathrm{~B}_3\)
- C \(\mathrm{A}_3 \mathrm{~B}_2\)
- D \(\mathrm{AB}_3\)
Answer & Solution
Correct Answer
(B) \(\mathrm{A}_2 \mathrm{~B}_3\)
Step-by-step Solution
Detailed explanation
Number of anions (B) in hcp = 6 Number of octahedral voids = 6
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