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MHT CET · Chemistry · Solid State

In an ionic solid anions are arranged in hcp array and cations occupy \(\frac{2}{3}\) of octahedral voids. What is the formula of ionic compound? [ consider \(\mathrm{A}=\) cation ; \(\mathrm{B}=\) anion]

  1. A AB
  2. B \(\mathrm{A}_2 \mathrm{~B}_3\)
  3. C \(\mathrm{A}_3 \mathrm{~B}_2\)
  4. D \(\mathrm{AB}_3\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\mathrm{A}_2 \mathrm{~B}_3\)

Step-by-step Solution

Detailed explanation

Number of anions (B) in hcp = 6 Number of octahedral voids = 6