MHT CET · Chemistry · Solid State
In an ionic crystalline solid, atoms of element \(Y\) forms hep structure. The atoms of element \(X\) occupy one third of tetrahedral voids. What is the formula of compound?
- A \(\mathrm{X}_2 \mathrm{Y}_3\)
- B \(X Y\)
- C \(\mathrm{X}_3 \mathrm{Y}_3\)
- D \(\mathrm{XY}_2\)
Answer & Solution
Correct Answer
(A) \(\mathrm{X}_2 \mathrm{Y}_3\)
Step-by-step Solution
Detailed explanation
The atoms of element \(\mathrm{Y}\) form hcp structure. The number of tetrahedral voids generated is twice the number of \(\mathrm{Y}\) atoms. Thus, number of tetrahedral voids \(=2 \mathrm{Y}\) The atoms of element \(X\) occupy (1/3) of these tetrahedral voids.
Hence, number of \(\mathrm{X}\) atoms \(=2 \mathrm{Y} \times 1 / 3=2 / 3 \mathrm{Y}\) Ratio of \(\mathrm{X}\) and \(\mathrm{Y}\) atoms \(=2 / 3 \mathrm{Y}: 1 \mathrm{Y}\) \(=2 / 3: 1=2: 3\)
\(\therefore \quad\) Formula of compound \(=\mathrm{X}_2 \mathrm{Y}_3\)
Hence, number of \(\mathrm{X}\) atoms \(=2 \mathrm{Y} \times 1 / 3=2 / 3 \mathrm{Y}\) Ratio of \(\mathrm{X}\) and \(\mathrm{Y}\) atoms \(=2 / 3 \mathrm{Y}: 1 \mathrm{Y}\) \(=2 / 3: 1=2: 3\)
\(\therefore \quad\) Formula of compound \(=\mathrm{X}_2 \mathrm{Y}_3\)
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