MHT CET · Chemistry · Thermodynamics (C)
In a process, a system performs \(238 \mathrm{~J}\) of work on it's surrounding by absorbing \(54 \mathrm{~J}\) of heat. What is the change in internal energy of system during this operation?
- A 222 J
- B -192 J
- C 54 J
- D -184 J
Answer & Solution
Correct Answer
(D) -184 J
Step-by-step Solution
Detailed explanation
Heat absorbed by the system is \((+)\) ve. Work done by the system is (-) ve.
\(
\begin{aligned}
& \mathrm{W}=-238 \mathrm{~J} \\
& \mathrm{q}=+54 \mathrm{~J} \\
& \Delta \mathrm{U}=\mathrm{q}+\mathrm{w} \\
& =54-238 \\
& =-184 \mathrm{~J}
\end{aligned}
\)
\(
\begin{aligned}
& \mathrm{W}=-238 \mathrm{~J} \\
& \mathrm{q}=+54 \mathrm{~J} \\
& \Delta \mathrm{U}=\mathrm{q}+\mathrm{w} \\
& =54-238 \\
& =-184 \mathrm{~J}
\end{aligned}
\)
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