MHT CET · Chemistry · Chemical Kinetics
In a first order reaction concentration of reactant decreases from 20 milli mol dm-3 to 8 milli mol dm-3 in 40 minute, find rate constant of reaction?
- A 0.011 minute \(^{-1}\)
- B 0.023 minute \(^{-1}\)
- C 0.032 minute \(^{-1}\)
- D 0.041 minute \(^{-1}\)
Answer & Solution
Correct Answer
(B) 0.023 minute \(^{-1}\)
Step-by-step Solution
Detailed explanation
\(k = \frac{1}{t} \ln\left(\frac{[A]_0}{[A]}\right)\) \(k = \frac{1}{40 \text{ min}} \ln\left(\frac{20 \text{ mmol dm}^{-3}}{8 \text{ mmol dm}^{-3}}\right)\)
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