MHT CET · Chemistry · Electrochemistry
In a certain electrolysis experiment, \(0.650 \mathrm{~g}\) of zinc is deposited in a cell having \(\mathrm{ZnSO}_4\) solution. Calculate mass of \(\mathrm{Cu}\) deposited in other cell having \(\mathrm{CuSO}_4\) solution arranged in series with first cell ? (molar mass of \(\mathrm{Zn}=65, \mathrm{Cu}=63.5 \mathrm{~g} \mathrm{~mol}^{-1}\) )
- A 0.635 g
- B 6.35 g
- C 0.317 g
- D 3.17 g
Answer & Solution
Correct Answer
(A) 0.635 g
Step-by-step Solution
Detailed explanation
\(\frac{W_1}{E_1}=\frac{W_2}{E_2}\)
\(\frac{0.65}{\frac{65}{2}}=\frac{W_2}{\frac{63.5}{2}}\)
\(W_2=0.635 \mathrm{~g}\)
\(\frac{0.65}{\frac{65}{2}}=\frac{W_2}{\frac{63.5}{2}}\)
\(W_2=0.635 \mathrm{~g}\)
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