MHT CET · Chemistry · States of Matter
If two moles of an ideal gas at \(546 \mathrm{~K}\) occupy a volume of \(44.8 \mathrm{~L}\). What is the pressure of ideal gas at
\(546 \mathrm{~K} ?\left(\mathrm{R}=0 \cdot 0821 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right)\)
- A 20 atm
- B \(0 \cdot 2\) atm
- C \(0 \cdot 5\) atm
- D \(2 \cdot 0\) atm
Answer & Solution
Correct Answer
(D) \(2 \cdot 0\) atm
Step-by-step Solution
Detailed explanation
\(\mathrm{n}=2 \mathrm{~mol}, \mathrm{~T}=546 \mathrm{~K}, \mathrm{~V}=44.8 \mathrm{~L}, \mathrm{R}\) \(=0.0821\)\(\mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}, \mathrm{P}=?\)
According to ideal gas equation,
\(\mathrm{PV}=\mathrm{n} \mathrm{R} \mathrm{T}\)
\(\therefore P=\frac{n R T}{V}=\frac{2 \times 0.0821 \times 546}{44.8}=2.0 \mathrm{~atm}\)
According to ideal gas equation,
\(\mathrm{PV}=\mathrm{n} \mathrm{R} \mathrm{T}\)
\(\therefore P=\frac{n R T}{V}=\frac{2 \times 0.0821 \times 546}{44.8}=2.0 \mathrm{~atm}\)
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