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MHT CET · Chemistry · States of Matter

If the mixture of \(7 g\) of \(N_2\) and \(8 g\) of \(\mathrm{Ar}\) in a cylinder has the total pressure \(27 \mathrm{bar}\). What is the partial pressure of \(N_2\) ? (Atomic mass of \(N=14 \mathrm{~g} \mathrm{~mol}^{-1}, \mathrm{Ar}=40 \mathrm{~g} \mathrm{~mol}^{-1}\) )

  1. A 18 bar
  2. B 12 bar
  3. C 15 bar
  4. D 9 bar
Verified Solution

Answer & Solution

Correct Answer

(C) 15 bar

Step-by-step Solution

Detailed explanation

Moles of \(N_2=\frac{7}{28}=\frac{1}{4}\)
Moles of \(\mathrm{Ar}=\frac{8}{40}=\frac{1}{5}\)
Partial pressure \(=X_{N_2} \times P_T\)
Partial pressure of
\(\begin{aligned}
N_2 & =\frac{\frac{1}{4}}{\frac{1}{4}+\frac{1}{5}} \times 27 \\
& =\frac{\frac{1}{4}}{\frac{9}{20}} \times 27 \\
& =\frac{1}{4} \times \frac{20}{9} \times 27 \\
& =15 \mathrm{bar}
\end{aligned}\)