MHT CET · Chemistry · Electrochemistry
If the conductivity of \(0.08 \mathrm{M}\) KCl solution is \(2 \times 10^{-2} \Omega^{-1}\), what is the molar conductivity of the solution?
- A 350 \(\Omega^{-1} \mathrm{Cm}^{2} \mathrm{mol}^{-1}\)
- B 250 \(\Omega^{-1} \mathrm{Cm}^{2} \mathrm{mol}^{-1}\)
- C 25.0 \(\Omega^{-1} \mathrm{Cm}^{2} \mathrm{mol}^{-1}\)
- D 0.25 \(\Omega^{-1} \mathrm{Cm}^{2} \mathrm{mol}^{-1}\)
Answer & Solution
Correct Answer
(B) 250 \(\Omega^{-1} \mathrm{Cm}^{2} \mathrm{mol}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\Lambda=\frac{1000 \mathrm{k}}{\mathrm{C}}=\frac{1000 \times 2 \times 10^{-2}}{0.08}=250 \Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}\)
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