MHT CET · Chemistry · Chemical Bonding and Molecular Structure
If 'Q' is the magnitude of charge and 'r' is the distance between the centres of positive and negative charges then dipole moment \((\mu)\) is given by
- A \(\mu=\mathrm{Q}+\mathrm{r}\)
- B \(\mu=Q \times r\)
- C \(\mu=\frac{\mathrm{Q}}{\mathrm{r}}\)
- D \(\mu=Q-r\)
Answer & Solution
Correct Answer
(B) \(\mu=Q \times r\)
Step-by-step Solution
Detailed explanation
If ' \(Q\) ' is the magnitude of charge and ' \(r\) ' is the distance between the centres of positive and negative charges then dipole moment \((\mu)\) is given by \(\boldsymbol{\mu}=\mathbf{Q} \times \mathbf{r}\).
Dipole moment \((\mu)\) is the product of the magnitude of the charge \((Q)\) and the distance between the centres of positive and negative charge (r).
\(\therefore \mu=Q \times r\)
Dipole moment \((\mu)\) is the product of the magnitude of the charge \((Q)\) and the distance between the centres of positive and negative charge (r).
\(\therefore \mu=Q \times r\)
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