MHT CET · Chemistry · States of Matter
If \(P_1\) partial pressure of a gas and \(x_1\) is its mole fraction in a mixture, then correct relation between \(P_1\) and \(x_1\) is
- A \(\mathrm{P}_{\text {total }}=\mathrm{P}_1 \mathrm{X}_1\)
- B \(\mathrm{x}_1=\frac{\mathrm{P}_1}{\mathrm{P}_{\text {total }}}\)
- C \(\mathrm{P}_{\text {total }}=1-\mathrm{P}_1 \mathrm{x}_1\)
- D \(\mathrm{P}_{\text {total }}=\mathrm{P}_1\left(1-\mathrm{x}_1\right)\)
Answer & Solution
Correct Answer
(B) \(\mathrm{x}_1=\frac{\mathrm{P}_1}{\mathrm{P}_{\text {total }}}\)
Step-by-step Solution
Detailed explanation
The correct relation between the partial pressure of a gas \(\left(P_1\right)\) and its mole fraction \(\left(x_1\right)\) in a mixture is given by Dalton's Law of Partial Pressures. According to this law, the partial pressure of a gas in a mixture is proportional to its mole fraction and the total pressure of the mixture. The expression can be written as:
\(P_1=x_1 \cdot P_{\text {total }}\)
From this relationship, we can derive the mole fraction as:
\(x_1=\frac{P_1}{P_{\text {total }}}\)
This corresponds to Option B:
\(x_1=\frac{P_1}{P_{\text {total }}}\)
\(P_1=x_1 \cdot P_{\text {total }}\)
From this relationship, we can derive the mole fraction as:
\(x_1=\frac{P_1}{P_{\text {total }}}\)
This corresponds to Option B:
\(x_1=\frac{P_1}{P_{\text {total }}}\)
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