MHT CET · Chemistry · Thermodynamics (C)
If lattice enthalpy and hydration enthalpy of \(\mathrm{KCl}\) are \(699 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and \(-681.8 \mathrm{~kJ} \mathrm{~mol}^{-1}\) respectively. What is the enthalpy of solution of \(\mathrm{KCl}\) ?
- A \(8.20 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- B \(10.25 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- C \(13.80 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- D \(17.20 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(D) \(17.20 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \Delta_{\text {soln }} \mathrm{H} & =\Delta_{\mathrm{L}} \mathrm{H}+\Delta_{\text {hyd }} \mathrm{H} \\ & =+699 \mathrm{~kJ} \mathrm{~mol}^{-1}+\left(-681.8 \mathrm{~kJ} \mathrm{~mol}^{-1}\right) \\ & =17.2 \mathrm{~kJ} \mathrm{~mol}^{-1}\end{aligned}\)
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