MHT CET · Chemistry · Electrochemistry
If \(E^{\circ}\left(\mathrm{Zn}_{(\mathrm{aq})}^{+2} \mid \mathrm{Zn}_{(\mathrm{s})}\right)=-0 \cdot 76 \mathrm{~V}\).
Calculate potential for \(\mathrm{Zn}_{(\mathrm{s})} \rightarrow \mathrm{Zn}_{(0.01 \mathrm{M})}^{+2}+2 \overline{\mathrm{e}}\) at 298 K ?
- A \(+0.8192 \mathrm{~V}\)
- B \(-0.8192\)
- C \(+0.7008 \mathrm{~V}\)
- D \(-0.7008 \mathrm{~V}\)
Answer & Solution
Correct Answer
(A) \(+0.8192 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
\(E^{\circ}_{\mathrm{oxidation}} = -E^{\circ}_{\mathrm{reduction}} = -(-0.76 \mathrm{~V}) = +0.76 \mathrm{~V}\) \(E = E^{\circ} - \frac{0.0592}{n} \log[\mathrm{Zn}^{+2}] \)
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