MHT CET · Chemistry · Thermodynamics (C)
If \(\Delta E\) is the heat of reaction for \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(\mathrm{l})+3 \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{CO}_{2}(\mathrm{~g})+3 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})\) at constant volume, the \(\Delta H\) (heat of reaction at constant pressure), at constant temperature is
- A \(\Delta H=\Delta E+R T\)
- B \(\Delta H=\Delta E-R T\)
- C \(\Delta H=\Delta E-2 R T\)
- D \(\Delta H=\Delta E+2 R T\)
Answer & Solution
Correct Answer
(B) \(\Delta H=\Delta E-R T\)
Step-by-step Solution
Detailed explanation
We know that, \(\Delta H=\Delta E+\Delta n R T\)
where, \(\Delta n=\) number of moles of gaseous products - number of moles of gaseous reactants
\(=2-3= -1 \)
\( \text {So, } \Delta H=\Delta E-R T\)
where, \(\Delta n=\) number of moles of gaseous products - number of moles of gaseous reactants
\(=2-3= -1 \)
\( \text {So, } \Delta H=\Delta E-R T\)
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