MHT CET · Chemistry · Chemical Kinetics
If concentration of reactant ' \(\mathrm{A}^{\prime}\) is increased by 10 times the rate of reaction becomes 100 times. What is the order of reaction if rate law is, rate \(=\mathrm{k}[\mathrm{A}]^{\mathrm{x}}\) ?
- A 1
- B 4
- C 3
- D 2
Answer & Solution
Correct Answer
(D) 2
Step-by-step Solution
Detailed explanation
(A)
\(r=k[A]^{x}, \quad 100 r=k[10 A]^{x}\)
\(\therefore \frac{1}{100}=\left(\frac{1}{10}\right)^{x}\)
\(\therefore x=2\)
The order of reaction \(=2\)
\(r=k[A]^{x}, \quad 100 r=k[10 A]^{x}\)
\(\therefore \frac{1}{100}=\left(\frac{1}{10}\right)^{x}\)
\(\therefore x=2\)
The order of reaction \(=2\)
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