MHT CET · Chemistry · Thermodynamics (C)
If bond formation energy of \(\mathrm{H}-\mathrm{H}\) bond is \(-433 \mathrm{~kJ} \mathrm{~mol}^{-1}\) find the bond dissociation energy for 0.5 mole \(\mathrm{H}_{2(\mathrm{~g})}\).
- A 108.0 kJ
- B 216.5 kJ
- C 433.0 kJ
- D 324.5 kJ
Answer & Solution
Correct Answer
(B) 216.5 kJ
Step-by-step Solution
Detailed explanation
For the given reaction,
\(\mathrm{H}_{2(\mathrm{~g})} \longrightarrow 2 \mathrm{H}_{(\mathrm{g})}, \Delta_{\mathrm{r}} \mathrm{H}^{\circ}=433 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
(Bond dissociation energy for 1 mole of \(\mathrm{H}_{2(\mathrm{~g})}\) \(=-\mathrm{H}-\mathrm{H}\) bond formation energy)
\(\therefore \quad\) Bond dissociation energy for 0.5 moles of \(\mathrm{H}_2=0.5 \times 433 \mathrm{~kJ}=216.5 \mathrm{~kJ}\)
\(\mathrm{H}_{2(\mathrm{~g})} \longrightarrow 2 \mathrm{H}_{(\mathrm{g})}, \Delta_{\mathrm{r}} \mathrm{H}^{\circ}=433 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
(Bond dissociation energy for 1 mole of \(\mathrm{H}_{2(\mathrm{~g})}\) \(=-\mathrm{H}-\mathrm{H}\) bond formation energy)
\(\therefore \quad\) Bond dissociation energy for 0.5 moles of \(\mathrm{H}_2=0.5 \times 433 \mathrm{~kJ}=216.5 \mathrm{~kJ}\)
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