If a metal crystallises in bcc structure with edge length of unit cell 4.29×10-8 cm the radius of metal atom is

MHT CET · Chemistry · Solid State

If a metal crystallises in bcc structure with edge length of unit cell $4.29 \times 10^{- 8}$ cm the radius of metal atom is

A $3.2 \times 10^{- 7} c m$
B $1.86 \times 10^{- 8} c m$
C $1.07 \times 10^{- 7} c m$
D $1.07 \times 10^{- 8} c m$

Verified Solution

Answer & Solution

Correct Answer

(B) $1.86 \times 10^{- 8} c m$

Step-by-step Solution

Detailed explanation

The relation between edge length and radius of an atom in a bcc structure is related as:

r = \sqrt{3} / 4 α

Given,

a = 4.29 \times 10^{- 8} c m

For bcc structure,

r = \frac{\sqrt{3}}{4} a = \frac{\sqrt{3}}{4} \times 4.29 \times 10^{- 8} c m

= 1.857 \times 10^{- 8} c m ≃ 1.86 \times 10^{- 8} c m

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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