MHT CET · Chemistry · States of Matter
If 2 moles of an ideal gas at \(546 \mathrm{~K}\) has volume of \(44 \cdot 8 \mathrm{~L}\), then what will be it's pressure ? \((\mathrm{R}=0.082)\)
- A 1.998atm
- B 1.098atm
- C 2.408atm
- D 3.129atm
Answer & Solution
Correct Answer
(A) 1.998atm
Step-by-step Solution
Detailed explanation
(D) \(\mathrm{n}=2\) moles \(, \mathrm{T}=546 \mathrm{~K}, \quad \mathrm{~V}=44.8 \mathrm{~L}\), \(\mathrm{R}=0.082, \quad \mathrm{P}=?\)
According to ideal gas equation, \(\mathrm{PV}=\mathrm{nRT} \quad \therefore \mathrm{P}=\frac{\mathrm{nRT}}{\mathrm{V}}\) \(\therefore \mathrm{P}=\frac{2 \times 0.082 \times 546}{44.8}=1.998 \mathrm{~atm}\)
According to ideal gas equation, \(\mathrm{PV}=\mathrm{nRT} \quad \therefore \mathrm{P}=\frac{\mathrm{nRT}}{\mathrm{V}}\) \(\therefore \mathrm{P}=\frac{2 \times 0.082 \times 546}{44.8}=1.998 \mathrm{~atm}\)
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