MHT CET · Chemistry · Electrochemistry
Identify the reaction taking place at anode during electrolysis of molten \(\mathrm{NaCl}\) ?
- A \(2 \mathrm{OH}^{-} \rightarrow \mathrm{H}_2 \mathrm{O}+\frac{1}{2} \mathrm{O}_2+2 \mathrm{e}^{-}\)
- B \(2 \mathrm{H}^{+} 2 \mathrm{e}^{-} \rightarrow \mathrm{H}_2\)
- C \(\mathrm{Na}^{+}+\mathrm{le}^{-} \rightarrow \mathrm{Na}_{(\mathrm{s})}\)
- D \(2 \mathrm{Cl}^{-} \rightarrow \mathrm{Cl}_{2(\mathrm{~g})}+2 \mathrm{e}^{-}\)
Answer & Solution
Correct Answer
(D) \(2 \mathrm{Cl}^{-} \rightarrow \mathrm{Cl}_{2(\mathrm{~g})}+2 \mathrm{e}^{-}\)
Step-by-step Solution
Detailed explanation
At anode oxidation takes place and \(\mathrm{Cl}^{-}\)ions get oxidized at anode,
\(2 \mathrm{Cl}^{-} \rightarrow \mathrm{Cl}_2+2 \mathrm{e}^{-}\)
\(2 \mathrm{Cl}^{-} \rightarrow \mathrm{Cl}_2+2 \mathrm{e}^{-}\)
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