MHT CET · Chemistry · Amines
Identify the product obtained when benzamide is treated with bromine and aqueous sodium hydroxide?
- A Bromobenzene
- B Phenol
- C Benzyl alcohol
- D Aniline
Answer & Solution
Correct Answer
(D) Aniline
Step-by-step Solution
Detailed explanation
Aniline
When benzamide is treated with bromine and aqueous sodium hydroxide, an aniline with one fewer carbon atom than the original amide is formed.
Reaction involved is as follows:
The Hofmann bromamide/degradation reaction is the name for this reaction. Aniline \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\right)\) will be the end product.
When benzamide is treated with bromine and aqueous sodium hydroxide, an aniline with one fewer carbon atom than the original amide is formed.
Reaction involved is as follows:
The Hofmann bromamide/degradation reaction is the name for this reaction. Aniline \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\right)\) will be the end product.
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