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MHT CET · Chemistry · Electrochemistry

Identify the overall oxidation reaction that occurs in lead storage cell during discharge.

  1. A \(\mathrm{Pb}_{(\mathrm{aq})}^{++}+\mathrm{SO}_{4(\mathrm{sq})}^{--} \longrightarrow \mathrm{PbSO}_{4(\mathrm{~s})}\)
  2. B \(\mathrm{PbSO}_{4(\mathrm{~s})}+2 \mathrm{H}_2 \mathrm{O}_{(0)} \longrightarrow \mathrm{PbO}_{2(\mathrm{~s})}+4\mathrm{H}_{(\mathrm{aq})}^{+}\) \(
    +\mathrm{SO}_{4(\mathrm{xq})}^{--}+2 \mathrm{e}^{-}
    \)
  3. C \(\mathrm{Pb}_{(8)}+\mathrm{SO}_{4(\mathrm{aq})}^{--} \longrightarrow \mathrm{PbSO}_{4(\mathrm{~s})}+2 \mathrm{e}^{-}\)
  4. D \(\quad \mathrm{PbSO}_{4(\mathrm{~s})}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Pb}_{(\mathrm{s})}+\mathrm{SO}_{4(\mathrm{mp})}^{--}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\mathrm{Pb}_{(8)}+\mathrm{SO}_{4(\mathrm{aq})}^{--} \longrightarrow \mathrm{PbSO}_{4(\mathrm{~s})}+2 \mathrm{e}^{-}\)

Step-by-step Solution

Detailed explanation

When the lead storage cell provides current (i.e., during discharge), spongy lead ( \(\mathrm{Pb}\) ) is oxidised to \(\mathrm{Pb}^{2+}\) ions and negative charge accumulates on lead plates. The \(\mathrm{Pb}^{2+}\) ions so formed combine with \(\mathrm{SO}_4^{2-}\) ions from \(\mathrm{H}_2 \mathrm{SO}_4\) to form insoluble \(\mathrm{PbSO}_4\). The overall oxidation is the sum of these two processes.
\(
\begin{aligned}
& \mathrm{Pb}_{(\mathrm{s})} \longrightarrow \mathrm{Pb}_{(\text {(4) }}^{2+}+2 \mathrm{e}^{-} \text { (oxidation) } \\
& \mathrm{Pb}_{(\text {(aq) }}^{2+}+\mathrm{SO}_{4(\text { (4) })}^{2-} \longrightarrow \mathrm{PbSO}_{4(\mathrm{~s})}\text {(precipitation) } \\
& \hline \mathrm{Pb}_{(\mathrm{s})}+\mathrm{SO}_{4(\text { (aq) }}^{2-} \longrightarrow \mathrm{PbSO}_{4(\mathrm{~s})}+2 \mathrm{e}^{-}
\end{aligned}
\)
(Overall oxidation)