MHT CET · Chemistry · Chemical Bonding and Molecular Structure
Identify the hybridisation and geometry of \(\mathrm{SF}_4\) molecule respectively.
- A \(\mathrm{sp}_3^3\) and tetrahedral
- B \(\mathrm{sp}_3^3\) and trigonal bipyramidal
- C \(\mathrm{sp}^3 \mathrm{~d}^2\) and trigonal bipyramidal
- D \(\mathrm{sp}^3 \mathrm{~d}\) and seesaw
Answer & Solution
Correct Answer
(D) \(\mathrm{sp}^3 \mathrm{~d}\) and seesaw
Step-by-step Solution
Detailed explanation
- Concept: \(S F_4\) has a seesaw shape, which corresponds to \(s p^3 d\) hybridization due to the presence of one lone pair and four bond pairs around the sulfur atom.
Answer: \(s p^3 d\) and seesaw (Trigonal bipyramidal class with asymmetric distribution due to lone pair).
Answer: \(s p^3 d\) and seesaw (Trigonal bipyramidal class with asymmetric distribution due to lone pair).
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