MHT CET · Chemistry · Classification of Elements and Periodicity in Properties
Identify the element having lowest first ionization enthalpy.
- A Po
- B Te
- C Br
- D Kr
Answer & Solution
Correct Answer
(A) Po
Step-by-step Solution
Detailed explanation
The ionization enthalpy (I.E) decreases down the group due to increase in the atomic size. Therefore, I.E of Te is more than that of Po. Across a period, I.E increases with increase of atomic number.
Therefore, I.E of Br and Kr is in the order: \(\mathrm{Br} \lt \mathrm{Kr}\).
Hence, the correct decreasing order of I.E for the given elements is: \(\mathrm{Kr}\gt\mathrm{Br}\gt\mathrm{Te}\gt\mathrm{Po}\)
Therefore, I.E of Br and Kr is in the order: \(\mathrm{Br} \lt \mathrm{Kr}\).
Hence, the correct decreasing order of I.E for the given elements is: \(\mathrm{Kr}\gt\mathrm{Br}\gt\mathrm{Te}\gt\mathrm{Po}\)
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