MHT CET · Chemistry · p Block Elements (Group 15, 16, 17 & 18)
Identify the correct decreasing order of thermal stability from following.
[Note: The question has been modified to get the correct answer.]
- A \(\mathrm{ClF}\gt\mathrm{ICl}\gt\mathrm{IBr}\gt\mathrm{BrCl}\)
- B \(\mathrm{BrCl}\gt\mathrm{IBr}\gt\mathrm{ICl}\gt\mathrm{ClF}\)
- C \(\mathrm{ClF}\gt\mathrm{IBr}\gt\mathrm{BrCl}\gt\mathrm{ICl}\)
- D \(\mathrm{ClF}\gt\mathrm{BrCl}\gt\mathrm{IBr}\gt\mathrm{ClF}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{ClF}\gt\mathrm{ICl}\gt\mathrm{IBr}\gt\mathrm{BrCl}\)
Step-by-step Solution
Detailed explanation
The thermal stability of interhalogen compounds depends upon the electronegativity of the combining atoms.
\(\begin{array}{|l|c|c|c|c|}
\hline \text { Elements } & \mathrm{F} & \mathrm{Cl} & \mathrm{Br} & \mathrm{I} \\
\hline \text { Electronegativity } & 4.0 & 3.2 & 3.0 & 2.7 \\
\hline
\end{array}\)
More the difference between the electronegativity the combining atoms, more is the thermal stability. Hence the order of thermal stability is \(\mathrm{ClF}>\mathrm{ICl}>\mathrm{IBr}>\mathrm{BrCl}\).
\(\begin{array}{|l|c|c|c|c|}
\hline \text { Elements } & \mathrm{F} & \mathrm{Cl} & \mathrm{Br} & \mathrm{I} \\
\hline \text { Electronegativity } & 4.0 & 3.2 & 3.0 & 2.7 \\
\hline
\end{array}\)
More the difference between the electronegativity the combining atoms, more is the thermal stability. Hence the order of thermal stability is \(\mathrm{ClF}>\mathrm{ICl}>\mathrm{IBr}>\mathrm{BrCl}\).
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