MHT CET · Chemistry · Surface Chemistry
Identify the correct decreasing order of precipitation power of flocculating ion added, from following.
- A \(\mathrm{Al}^{3+}>\mathrm{Na}^{+} \mathrm{Ba}^{2+}\)
- B \(\mathrm{Ba}^{2+}>\mathrm{Al}^{3+}>\mathrm{Na}^{+}\)
- C \(\mathrm{Al}^{3+}>\mathrm{Ba}^{2+}>\mathrm{Na}^{+}\)
- D \(\mathrm{Na}^{+}>\mathrm{Ba}^{2+}>\mathrm{Al}^{3+}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{Al}^{3+}>\mathrm{Ba}^{2+}>\mathrm{Na}^{+}\)
Step-by-step Solution
Detailed explanation
Higher is the valency of ion or charge of ion more will be its precipitation power.
\(
\mathrm{Al}^{3+}>\mathrm{Ba}^{2+}>\mathrm{Na}^{+}
\)
\(
\mathrm{Al}^{3+}>\mathrm{Ba}^{2+}>\mathrm{Na}^{+}
\)
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