MHT CET · Chemistry · Ionic Equilibrium
Identify the conjugate acid-base pair respectively from following equilibrium reaction.
\(\mathrm{HPO}_{4(\mathrm{aq})}^{2-}+\mathrm{H}_2 \mathrm{O}_{(\ell)} \rightleftharpoons \mathrm{PO}_{4(\mathrm{aq})}^{3-}+\mathrm{H}_3 \mathrm{O}_{(\mathrm{aq})}^{+}\)
- A \(\mathrm{H}_3 \mathrm{O}^{+}\)and \(\mathrm{H}_2 \mathrm{O}\)
- B \(\mathrm{H}_2 \mathrm{O}\) and \(\mathrm{HPO}_4^{2-}\)
- C \(\mathrm{PO}_4^{3-}\) and \(\mathrm{H}_3 \mathrm{O}^{+}\)
- D \(\mathrm{H}_3 \mathrm{O}^{+}\)and \(\mathrm{HPO}_4{ }^{2-}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{H}_3 \mathrm{O}^{+}\)and \(\mathrm{H}_2 \mathrm{O}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{HPO}_{4}^{2-}\) acts as an acid (proton donor) and \(\mathrm{PO}_{4}^{3-}\) is its conjugate base. \(\mathrm{H}_2 \mathrm{O}\) acts as a base (proton acceptor) and \(\mathrm{H}_3 \mathrm{O}^{+}\) is its conjugate acid.
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