MHT CET · Chemistry · Biomolecules
Identify the carbon atoms of \(\alpha\)-glucose and \(\beta\)-fructose forming glycosidic linkage in sucrose.
- A \(\mathrm{C}\) - 1 of \(\beta\)-fructose and \(\mathrm{C}\) - 2 of \(\alpha\)-glucose
- B \(\mathrm{C}-1\) of \(\alpha\)-glucose and \(\mathrm{C}-2\) of \(\beta\)-fructose
- C \(\mathrm{C}-1\) of \(\alpha\)-glucose and \(\mathrm{C}-1\) of \(\beta\)-fructose
- D \(\mathrm{C}-2\) of \(\alpha\)-glucose and \(\mathrm{C}-2\) of \(\beta\)-fructose
Answer & Solution
Correct Answer
(B) \(\mathrm{C}-1\) of \(\alpha\)-glucose and \(\mathrm{C}-2\) of \(\beta\)-fructose
Step-by-step Solution
Detailed explanation
Structure of sucrose contains glycosidic linkage between - \(\mathrm{C}-1\) of \(\alpha\)-glucose and \(\mathrm{C}-2\) of \(\beta\)-fructose. Aldehyde and ketone groups of both the monosaccharide units are involved in formation of the glycosidic bond.
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