MHT CET · Chemistry · Haloalkanes and Haloarenes
Identify ' B ' in the following conversion.
\(\mathrm{CH}_3-\mathrm{I} \xrightarrow{\mathrm{KCN}} \mathrm{~A} \xrightarrow{\mathrm{Na} / \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}} \mathrm{O}\)
- A \(\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CN}\)
- B \(\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_3\)
- C \(\mathrm{CH}_3-\mathrm{NH}-\mathrm{C}_2 \mathrm{H}_5\)
- D \(\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{NH}_2\)
Answer & Solution
Correct Answer
(D) \(\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{NH}_2\)
Step-by-step Solution
Detailed explanation
\(\underset{\begin{array}{c}
\text { Methyl } \\
\text { iodide }
\end{array}}{\mathrm{CH}_3-\mathrm{I}}+\underset{\text { (alc.) }}{\mathrm{KCN}} \longrightarrow \underset{\begin{array}{c}
\text { Methyl } \\
\text { cyanide }
\end{array}}{\mathrm{CH}_3-\mathrm{CN}}+\mathrm{KI}\)
(A)
\(\mathrm{CH}_3-\mathrm{CN}+4[\mathrm{H}] \xrightarrow{\mathrm{Na} / \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}} \underset{\text { Ethylamine (B) }}{\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{NH}_2}\)
\text { Methyl } \\
\text { iodide }
\end{array}}{\mathrm{CH}_3-\mathrm{I}}+\underset{\text { (alc.) }}{\mathrm{KCN}} \longrightarrow \underset{\begin{array}{c}
\text { Methyl } \\
\text { cyanide }
\end{array}}{\mathrm{CH}_3-\mathrm{CN}}+\mathrm{KI}\)
(A)
\(\mathrm{CH}_3-\mathrm{CN}+4[\mathrm{H}] \xrightarrow{\mathrm{Na} / \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}} \underset{\text { Ethylamine (B) }}{\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{NH}_2}\)
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