MHT CET · Chemistry · Solid State
How many total voids are present in 1 mole of compound that forms hcp structure?
- A \(1.806 \times 10^{24}\)
- B \(1.204 \times 10^{24}\)
- C \(3.011 \times 10^{23}\)
- D \(6.022 \times 10^{23}\)
Answer & Solution
Correct Answer
(A) \(1.806 \times 10^{24}\)
Step-by-step Solution
Detailed explanation
In HCP structure
For each atom total three voids are present (one octahedral and two tetrahedral) Number of atoms in \(1 \mathrm{~mol}\) of compound \(=6.022 \times 10^{23}\)
Total number of voids \(=\) No. of atoms \(\times 3\)
\(
\begin{aligned}
& =6.022 \times 10^{23} \times 23 \\
& =18.06 \times 10^{23} \\
& =1.806 \times 10^{24}
\end{aligned}
\)
For each atom total three voids are present (one octahedral and two tetrahedral) Number of atoms in \(1 \mathrm{~mol}\) of compound \(=6.022 \times 10^{23}\)
Total number of voids \(=\) No. of atoms \(\times 3\)
\(
\begin{aligned}
& =6.022 \times 10^{23} \times 23 \\
& =18.06 \times 10^{23} \\
& =1.806 \times 10^{24}
\end{aligned}
\)
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