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MHT CET · Chemistry · States of Matter

How many moles of dioxygen are present in \(8.314 \times 10^{-3} \mathrm{~m}^3\) of it at 318 K having pressure \(3.18 \times 10^5 \mathrm{Nm}^{-2} ?\left(\mathrm{R}=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)\)

  1. A 0.1 mole
  2. B 1.0 mole
  3. C 1.5 mole
  4. D 2.0 mole
Verified Solution

Answer & Solution

Correct Answer

(B) 1.0 mole

Step-by-step Solution

Detailed explanation

\(\mathrm{n}=\frac{\mathrm{PV}}{\mathrm{RT}}=\frac{3.18 \times 10^5 \mathrm{~N} \mathrm{m}^{-2} \times 8.314 \times 10^{-3} \mathrm{~m}^3}{8.314 \mathrm{~J} \mathrm{K}^{-1} \mathrm{~mol}^{-1} \times 318 \mathrm{~K}} \)
\(=\frac{26.438 \times 10^2 \mathrm{~N} \mathrm{~m}}{8.314 \mathrm{~J} \mathrm{~mol}^{-1} \times 318}(\because 1 \mathrm{~N} \mathrm{~m}=1 \text { Joule})\)
\( \therefore \mathrm{n}=\frac{26.438 \mathrm{~J} \times 10^2}{2643.85 \mathrm{~J} \mathrm{~mol}^{-1}}=1 \mathrm{~mole}\)