MHT CET · Chemistry · Redox Reactions
How many mole of electron are required fro the reduction of 1 mole of \(\mathrm{Cr}^3+\) to \(\mathrm{Cr}_{(\mathrm{s})}\) ?
- A \(3\)
- B \(6\)
- C \(1\)
- D \(\frac{6.022 \times 10^{23}}{3}\)
Answer & Solution
Correct Answer
(A) \(3\)
Step-by-step Solution
Detailed explanation
\(\underset{1 \mathrm{mo1}}{\mathrm{Cr}^{+3}}+\underset{3 \mathrm{mo1}}{3 \mathrm{e}^{-}} \rightarrow \mathrm{Cr}(\mathrm{s})\)
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