MHT CET · Chemistry · Redox Reactions
How many gram-equivalents of \(\mathrm{NaOH}\) are required to neutralise \(25 \mathrm{~cm}^{3}\) of a decinormal \(\mathrm{HCl}\) solution?
- A \(0.00125\)
- B \(0.0025\)
- C \(0.0050\)
- D \(0.025\)
Answer & Solution
Correct Answer
(B) \(0.0025\)
Step-by-step Solution
Detailed explanation
For acid-base reactions, g-equivalent of acid \(=\) g-equivalent of base
\((\mathrm{HCl}) (\mathrm{NaOH})\)
\(\therefore \text {g-equivalent of acid }=\) \(\left(25 \times 10^{-3}\right) \mathrm{dm}^{3} \times \frac{1}{10}\)
\(= 25 \times 10^{-4}\)
\(\text {or } =0.0025\)
\(=\mathrm{g}\) -equivalent of \(\mathrm{NaOH}\)
\((\mathrm{HCl}) (\mathrm{NaOH})\)
\(\therefore \text {g-equivalent of acid }=\) \(\left(25 \times 10^{-3}\right) \mathrm{dm}^{3} \times \frac{1}{10}\)
\(= 25 \times 10^{-4}\)
\(\text {or } =0.0025\)
\(=\mathrm{g}\) -equivalent of \(\mathrm{NaOH}\)
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