MHT CET · Chemistry · Electrochemistry
How many faradays of electricity is required to produce \(4.8 \mathrm{~g}\) of \(\mathrm{Mg}\) at cathode in the electrolysis of molten \(\mathrm{MgCl}_{2} ?\) (Molar mass of \(\mathrm{Mg}=24 \mathrm{~g} / \mathrm{mol}\) )
- A \(0.4 \mathrm{~F}\)
- B \(4 \mathrm{~F}\)
- C \(10 \mathrm{~F}\)
- D \(\mathrm{~F}\)
Answer & Solution
Correct Answer
(A) \(0.4 \mathrm{~F}\)
Step-by-step Solution
Detailed explanation
(A)
\(\mathrm{Mg}^{2+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Mg}\) (at cathode)
\(24 \mathrm{~g}\) of \(\mathrm{Mg}=2 \mathrm{~F}\) of electricity
\(\therefore 4.8 \mathrm{~g}\) of \(\mathrm{Mg}=\frac{4.8 \times 2}{24}=0.4 \mathrm{~F}\) of electricity.
\(\mathrm{Mg}^{2+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Mg}\) (at cathode)
\(24 \mathrm{~g}\) of \(\mathrm{Mg}=2 \mathrm{~F}\) of electricity
\(\therefore 4.8 \mathrm{~g}\) of \(\mathrm{Mg}=\frac{4.8 \times 2}{24}=0.4 \mathrm{~F}\) of electricity.
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