MHT CET · Chemistry · Electrochemistry
How many Faraday of electricity is required to produce \(5 \mathrm{~g}\) of magnesium from magnesium chloride?
(Molar mass Mg \(=24 \mathrm{~g} \mathrm{~mol}^{-1}\) )
- A \(2.451 \mathrm{~F}\)
- B \(0.417 \mathrm{~F}\)
- C \(6.0 \mathrm{~F}\)
- D \(9.634 \mathrm{~F}\)
Answer & Solution
Correct Answer
(B) \(0.417 \mathrm{~F}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{Mg}^{+2}+2 \mathrm{e}^{-} \rightarrow \mathrm{Mg} \)
\( 2 \mathrm{~mol} \quad 1 \mathrm{~mol} \)
\( \frac{5}{24}=0.208 \mathrm{~mol} \mathrm{Mg} \)
\( \therefore \text { Mol of charge required or faraday}\) \(\text{of change required } \)
\( =0.208 \times 2 \)
\( =0.416 \mathrm{~F}\)
\( 2 \mathrm{~mol} \quad 1 \mathrm{~mol} \)
\( \frac{5}{24}=0.208 \mathrm{~mol} \mathrm{Mg} \)
\( \therefore \text { Mol of charge required or faraday}\) \(\text{of change required } \)
\( =0.208 \times 2 \)
\( =0.416 \mathrm{~F}\)
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