MHT CET · Chemistry · Thermodynamics (C)
Heat of combustion of methane is \(-800 \mathrm{~kJ}\). What is the heat of combustion for \(4 \times 10^{-4} \mathrm{~kg}\) of methane?
- A \(-800 \mathrm{~kJ}\)
- B \(-3.2 \times 10^{4} \mathrm{~kJ}\)
- C \(-20 \mathrm{~kJ}\)
- D \(-1600 \mathrm{~kJ}\)
Answer & Solution
Correct Answer
(C) \(-20 \mathrm{~kJ}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{CH}_{4}+2 \mathrm{O}_{2} \longrightarrow \mathrm{CO}_{2}+2 \mathrm{H}_{2} \mathrm{O} ; \Delta H_{c}=-800 \mathrm{~kJ}\)
\(16 \mathrm{~g}\)
\(\because\) Heat of combustion of \(16 \times 10^{-3} \mathrm{~kg}\) \(\mathrm{CH}_{4}=-800 \mathrm{~kJ}\)
\(\therefore\) Heat of combustion of \(4 \times 10^{-4} \mathrm{~kg} \mathrm{CH}_{4}\) will be
\(
\begin{array}{l}
=-\frac{800 \times 4 \times 10^{-4}}{16 \times 10^{-3}} \\
=-20 \mathrm{~kJ}
\end{array}
\)
\(16 \mathrm{~g}\)
\(\because\) Heat of combustion of \(16 \times 10^{-3} \mathrm{~kg}\) \(\mathrm{CH}_{4}=-800 \mathrm{~kJ}\)
\(\therefore\) Heat of combustion of \(4 \times 10^{-4} \mathrm{~kg} \mathrm{CH}_{4}\) will be
\(
\begin{array}{l}
=-\frac{800 \times 4 \times 10^{-4}}{16 \times 10^{-3}} \\
=-20 \mathrm{~kJ}
\end{array}
\)
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