MHT CET · Chemistry · Thermodynamics (C)
For the reaction, \(\mathrm{N}_{2_{(\mathrm{g})}}+3 \mathrm{H}_{2_{(\mathrm{g})}} \rightarrow 2 \mathrm{NH}_{3_{(\mathrm{g})}} \Delta \mathrm{H}\) is equal to
- A \(\Delta \mathrm{U}+\mathrm{RT}\)
- B \(\Delta \mathrm{U}+2 \mathrm{RT}\)
- C \(\Delta \mathrm{U}-\mathrm{RT}\)
- D \(\Delta \mathrm{U}-2 \mathrm{RT}\)
Answer & Solution
Correct Answer
(D) \(\Delta \mathrm{U}-2 \mathrm{RT}\)
Step-by-step Solution
Detailed explanation
(D)
\(\mathrm{N}_{2(\boldsymbol{g})}+3 \mathrm{H}_{2(\boldsymbol{g})} \longrightarrow 2 \mathrm{NH}_{3(\boldsymbol{g})}\)
\(\therefore \Delta n=2-4=-2\)
\(\therefore \Delta H=\Delta U+\Delta n R T=\Delta U-2 R T\)
\(\mathrm{N}_{2(\boldsymbol{g})}+3 \mathrm{H}_{2(\boldsymbol{g})} \longrightarrow 2 \mathrm{NH}_{3(\boldsymbol{g})}\)
\(\therefore \Delta n=2-4=-2\)
\(\therefore \Delta H=\Delta U+\Delta n R T=\Delta U-2 R T\)
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