MHT CET · Chemistry · Thermodynamics (C)
For the reaction, \(\mathrm{C}_3 \mathrm{H}_{8(\mathrm{~g})}+5 \mathrm{O}_{2(\mathrm{~g})} \longrightarrow 3 \mathrm{CO}_{2(\mathrm{~g})}+4 \mathrm{H}_2 \mathrm{O}_{(\mathrm{i})}\) at constant temperature, \(\Delta \mathrm{H}-\Delta \mathrm{U}\) is
- A \(-2 \mathrm{RT}\)
- B RT
- C \(-3 R T\)
- D 3 RT
Answer & Solution
Correct Answer
(C) \(-3 R T\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
& \mathrm{C}_3 \mathrm{H}_{8(\mathrm{~g})}+5 \mathrm{O}_{2(\mathrm{~g})} \rightarrow 3 \mathrm{CO}_{2(\mathrm{~g})}+4 \mathrm{H}_2 \mathrm{O}_{(\mathrm{l}} \\
& \Delta \mathrm{ng}_{\mathrm{g}}=3-(1+5)=-3 \mathrm{~mol}
\end{aligned}\)
Now,
\(\begin{array}{ll}
& \Delta H=\Delta U+\Delta n_g R T \\
\therefore & \Delta H=\Delta U+(-3) R T \\
\therefore & \Delta H-\Delta U=-3 R T
\end{array}\)
& \mathrm{C}_3 \mathrm{H}_{8(\mathrm{~g})}+5 \mathrm{O}_{2(\mathrm{~g})} \rightarrow 3 \mathrm{CO}_{2(\mathrm{~g})}+4 \mathrm{H}_2 \mathrm{O}_{(\mathrm{l}} \\
& \Delta \mathrm{ng}_{\mathrm{g}}=3-(1+5)=-3 \mathrm{~mol}
\end{aligned}\)
Now,
\(\begin{array}{ll}
& \Delta H=\Delta U+\Delta n_g R T \\
\therefore & \Delta H=\Delta U+(-3) R T \\
\therefore & \Delta H-\Delta U=-3 R T
\end{array}\)
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