MHT CET · Chemistry · Chemical Kinetics
For the reaction \(2 \mathrm{NO}+\mathrm{Cl}_2 \rightarrow 2 \mathrm{NOCl}\)
What is the relation between \(\frac{\mathrm{d}[\mathrm{NO}]}{\mathrm{dt}}\) and \(\frac{\mathrm{d}[\mathrm{NOCl}]}{\mathrm{dt}}\)
- A \(\frac{\mathrm{d}[\mathrm{NO}]}{\mathrm{dt}}=2 \frac{\mathrm{d}[\mathrm{NOCl}]}{\mathrm{dt}}\)
- B \(\frac{\mathrm{d}[\mathrm{NO}]}{\mathrm{dt}}=\frac{\mathrm{d}[\mathrm{NOCl}]}{\mathrm{dt}}\)
- C \(\frac{1}{4} \frac{\mathrm{d}[\mathrm{NO}]}{\mathrm{dt}}=\frac{\mathrm{d}[\mathrm{NOCl}]}{\mathrm{dt}}\)
- D \(4 \frac{\mathrm{d}[\mathrm{NO}]}{\mathrm{dt}}=\frac{\mathrm{d}[\mathrm{NOCl}]}{\mathrm{dt}}\)
Answer & Solution
Correct Answer
(B) \(\frac{\mathrm{d}[\mathrm{NO}]}{\mathrm{dt}}=\frac{\mathrm{d}[\mathrm{NOCl}]}{\mathrm{dt}}\)
Step-by-step Solution
Detailed explanation
\(
2 \mathrm{NO}+\mathrm{Cl}_2 \longrightarrow 2 \mathrm{NOCl}
\)
Stoichiometric co-efficients of No and \(\mathrm{NOCl}\) are same So their rates will be equal.
\(
\frac{\mathrm{d}[\mathrm{NO}]}{\mathrm{dt}}=\frac{\mathrm{d}[\mathrm{NOCl}]}{\mathrm{dt}}
\)
2 \mathrm{NO}+\mathrm{Cl}_2 \longrightarrow 2 \mathrm{NOCl}
\)
Stoichiometric co-efficients of No and \(\mathrm{NOCl}\) are same So their rates will be equal.
\(
\frac{\mathrm{d}[\mathrm{NO}]}{\mathrm{dt}}=\frac{\mathrm{d}[\mathrm{NOCl}]}{\mathrm{dt}}
\)
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