MHT CET · Chemistry · Chemical Kinetics
For the reaction,
\(2 \mathrm{NO}_{2(\mathrm{~g})} \rightarrow 2 \mathrm{NO}_{(\mathrm{g})}+\mathrm{O}_{2(\mathrm{~g})}, \frac{\mathrm{d}\left[\mathrm{NO}_2\right]}{\mathrm{dt}}\) is \(1.3 \times 10^{-5} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{sec}^{-1}\),
What is rate of \(\mathrm{O}_2\) ?
- A \(1.3 \times 10^{-6} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{sec}^{-1}\)
- B \(3.25 \times 10^{-6} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{sec}^{-1}\)
- C \(1.62 \times 10^{-6} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{sec}^{-1}\)
- D \(6.5 \times 10^{-6} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{sec}^{-1}\)
Answer & Solution
Correct Answer
(D) \(6.5 \times 10^{-6} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{sec}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & -\frac{1}{2} \frac{\mathrm{d}\left[\mathrm{NO}_2\right]}{\mathrm{dt}}=\frac{\mathrm{d}\left[\mathrm{O}_2\right]}{\mathrm{dt}} \\ & \frac{1}{2}\left(1.3 \times 10^{-5}\right)=\frac{\mathrm{d}\left[\mathrm{O}_2\right]}{\mathrm{dt}} \\ & \frac{\mathrm{d}\left[\mathrm{O}_2\right]}{\mathrm{dt}}=6.5 \times 10^{-6} \frac{\mathrm{mo} 1}{\mathrm{~L}-\mathrm{sec}}\end{aligned}\)
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