MHT CET · Chemistry · Thermodynamics (C)
For the reaction \(2 H _2+ O _2 \rightarrow 2 H _2 O , \rightarrow \Delta H =-571\). Bond energy of \(H - H =435\) and \(O = O =498\). Then the average bond energy of \(O - H\) bond will be
- A 484
- B -484
- C 271
- D -271
Answer & Solution
Correct Answer
(A) 484
Step-by-step Solution
Detailed explanation
For the reaction
\(2 H_2+O_2 \rightarrow 2 H_2 O(2 H-O-H) \)
\( \Delta_{r} H=2 \times BE\left(H_2\right)+BE\left(O_2\right)-4\) \(\times~ BE(O-H) \)
\( -571=2 \times 435+498-4 \times BE(O-H) \)
\( \text { or } BE(O-H)=484\)
\(2 H_2+O_2 \rightarrow 2 H_2 O(2 H-O-H) \)
\( \Delta_{r} H=2 \times BE\left(H_2\right)+BE\left(O_2\right)-4\) \(\times~ BE(O-H) \)
\( -571=2 \times 435+498-4 \times BE(O-H) \)
\( \text { or } BE(O-H)=484\)
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