MHT CET · Chemistry · Chemical Kinetics
For the reaction. \(2 \mathrm{~A}+\mathrm{B} \rightarrow 2 \mathrm{C}\), rate of disappearance of \(\mathrm{A}\) is \(0.076 \mathrm{~mol} \mathrm{~s}^{-1}\). What is the rate of disappearance of B?
- A \(0.076 \mathrm{~mol} \mathrm{~s}^{-1}\)
- B \(0.038 \mathrm{~mol} \mathrm{~s}^{-1}\)
- C \(0.019 \mathrm{~mol} \mathrm{~s}^{-1}\)
- D \(0.095 \mathrm{~mol} \mathrm{~s}^{-1}\)
Answer & Solution
Correct Answer
(B) \(0.038 \mathrm{~mol} \mathrm{~s}^{-1}\)
Step-by-step Solution
Detailed explanation
\(2 \mathrm{~A}+\mathrm{B} \longrightarrow 2 \mathrm{C}\)
\(\frac{\text { Rate of disappearance of A }}{2}=\frac{\text { Rate of disappearance of B }}{1}\)
Rate of disappearance of \(\mathrm{B}=\frac{1}{2} \times 0.076\)
\(=0.038 \mathrm{~mol} \mathrm{~s}^{-1}\)
\(\frac{\text { Rate of disappearance of A }}{2}=\frac{\text { Rate of disappearance of B }}{1}\)
Rate of disappearance of \(\mathrm{B}=\frac{1}{2} \times 0.076\)
\(=0.038 \mathrm{~mol} \mathrm{~s}^{-1}\)
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